Use the balanced equation to solve the problem.

Na2CO3 + CaCh -* 2NaCI + CaCO3

139g Na2CO3 and 95.0g CaCly are mixed in solution and react.

How many moles Na2CO3 are available to react?

How many moles CaCl2 are available to react?

What is the limiting reactant?

How many grams of CaCO3 are made?